There are 12 different divisibility tests. They are the numbers 2-12. This link shows all the different steps LINK.
The divisibility of 7 and 11 are really difficult and hard to solve.
7 is very difficult and recommended that you just do the division.
11 can be solved by finding the sumo of the odd-numbered digits (odd sum) and the sum of the even numbered digits (even sum). Take the difference between the odd and the even sum. If this difference is divisible by 11, then the original number is divisible by eleven.
7204857. You add the odd numbered digits 7+0+8+7=22
Then you take the even numbered digits and add them. 2+4+5=11
Subtract 22-11=11.
11 is divisible by 11 so you know that 7204857 is divisible by 11.
This video will help you if need some more help.
GCF and LCM
14 years ago
Nice heading Jordan. Good posting.
ReplyDeleteI hadn't seen that idea for divisibility by 8 - that is, take half, then check for divisibility by 4. That might be easier in many cases!
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